Spring中Bean的种类及作用域

解决JDK版本导致JMeter无法启动问题

SomethingBeTrue:

修改后启动jmeter.bat,还会报一个WARNING,需要以管理员权限执行一次后,这个警告才不会再提示;

【搞定算法】找出数组中出现次数大于数组长度一半和 N/K 的数

m0_47471640:

看一下要求,要求空间复杂度o1

【手撕代码】多个线程交替打印

程序员的暴击:

在给你补一个

[code=java]

public class PrintByPark {

static Thread a;

static Thread b;

static Thread c;

public static void main(String[] args) {

ParkUnPark parkUnPark = new ParkUnPark(5);

a = new Thread(() -> parkUnPark.print("a", b));

b = new Thread(() -> parkUnPark.print("b", c));

c = new Thread(() -> parkUnPark.print("c", a));

a.start();

b.start();

c.start();

LockSupport.unpark(a);

}

}

class ParkUnPark{

private final int loopNum;

public ParkUnPark(int loopNum) {

this.loopNum = loopNum;

}

public void print(String content, Thread next){

for (int i = 0; i < loopNum; i++) {

LockSupport.park();

System.out.println(content);

LockSupport.unpark(next);

}

}

}

[/code]

【leetcode】第5题:最长回文子串

程序员的暴击:

[code=java]

public static String longestPalindrome(String str){

String reserveString = new StringBuilder(str).reverse().toString();

int len1 = str.length(),len2 = reserveString.length();

int[][] lenArr = new int[len1][len2];

int maxLen = 0,maxEndStrlen = 0;

for (int i = 0; i < len1; i++) {

for (int j = 0; j < len2; j++) {

if (str.charAt(i) == reserveString.charAt(j)){

if (i ==0 || j==0){

lenArr[i][j] = 0;

}

else {

lenArr[i][j] = lenArr[i-1][j-1] + 1;

}

}

if ( lenArr[i][j] > maxLen){

maxLen = lenArr[i][j];

maxEndStrlen = i;

}

}

}

return str.substring(maxEndStrlen - maxLen + 1 ,maxEndStrlen +1);

}

[/code]

字符串的排列与组合【Java 递归实现】

程序员的暴击:

全排列

[code=java]

public static List> permute(int[] nums) {

List> list = new ArrayList<>();

backtrack(list, new LinkedList<>(), nums);

return list;

}

private static void backtrack(List> list, LinkedList tempList, int[] nums){

if (tempList.size() == nums.length) {

list.add(new ArrayList<>(tempList));

}

else {

for (int num : nums) {

if (tempList.contains(num)) {

continue;

}

tempList.add(num);

backtrack(list, tempList, nums);

tempList.removeLast();

}

}

}

[/code]

2025-08-04 12:24:04
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